sum of digits in java

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class TestJava {
public static int sumOfDigits(int number){
if (number < 10) return -1;
int sum = 0;
while (number > 10){
sum += number
number /= 10;
}
return sum + number;
}
public static void main(String[] args) {
int number = 234567;
int sumOfDigits = sumOfDigits(number);
System.out.println("Number: " + number);
System.out.println("Sum Of Digits: " + sumOfDigits);
}
}
class TestJava { public static int sumOfDigits(int number){ if (number < 10) return -1; int sum = 0; while (number > 10){ sum += number number /= 10; } return sum + number; } public static void main(String[] args) { int number = 234567; int sumOfDigits = sumOfDigits(number); System.out.println("Number: " + number); System.out.println("Sum Of Digits: " + sumOfDigits); } }
class TestJava {
	public static int sumOfDigits(int number){
          if (number < 10) return -1;
          int sum = 0;
          while (number > 10){
             sum += number
            number /= 10;
          }
          return sum + number;
	}
	
	public static void main(String[] args) {
		int number = 234567;		
		int sumOfDigits = sumOfDigits(number);
		
		System.out.println("Number: " + number);		
		System.out.println("Sum Of Digits: " + sumOfDigits);		
	}
}

Output:

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Number: 234567
Sum Of Digits: 27
Number: 234567 Sum Of Digits: 27
Number: 234567
Sum Of Digits: 27